Exercises on Bonding and Molecular Geometry

Exercise 1

Boron Trifluoride (BF3)

Task: Determine the molecular geometry and hybridization.

해답 보기

Answer Explanation:

BF3 has a trigonal planar geometry with sp2 hybridization. Boron has three bonding pairs and no lone pairs.

Correct Answer: Trigonal Planar, sp2


Exercise 2

Phosphorus Trichloride (PCl3)

Task: Determine the molecular geometry and hybridization.

해답 보기

Answer Explanation:

PCl3 has a trigonal pyramidal geometry with sp3 hybridization. Phosphorus has three bonding pairs and one lone pair.

Correct Answer: Trigonal Pyramidal, sp3


Exercise 3

Triiodide Ion (I3)

Task: Determine the molecular geometry and hybridization.

해답 보기

Answer Explanation:

I3 has a linear geometry with sp3d hybridization. The central iodine has two bonding pairs and three lone pairs.

Correct Answer: Linear, sp3d


Exercise 4

Nitrite Ion (NO2)

Task: Determine the molecular geometry and hybridization.

해답 보기

Answer Explanation:

NO2 has a bent geometry with sp2 hybridization. Nitrogen has two bonding pairs and one lone pair.

Correct Answer: Bent, sp2


Exercise 5

Nitrate Ion (NO3)

Task: Determine the molecular geometry and hybridization.

해답 보기

Answer Explanation:

NO3 has a trigonal planar geometry with sp2 hybridization. Nitrogen has three bonding pairs and no lone pairs.

Correct Answer: Trigonal Planar, sp2


Exercise 6

Which of the following compounds has the highest lattice energy?

  • (A) Sodium Chloride (NaCl)
  • (B) Lithium Fluoride (LiF)
  • (C) Magnesium Oxide (MgO)
  • (D) Potassium Bromide (KBr)
해답 보기

Answer Explanation:

Lattice energy increases with higher charges on the ions and smaller ionic radii. Magnesium oxide (MgO) has Mg2+ and O2-, so it has a higher lattice energy than the other compounds.

Correct Answer: (C) MgO


Exercise 7

Which of the following substances is most likely to form an ionic bond based on its properties?

  • (A) Gold (Au)
  • (B) Sodium Chloride (NaCl)
  • (C) Methane (CH4)
  • (D) Carbon Dioxide (CO2)
View Answer

Answer Explanation:

Ionic bonds typically form between metals and nonmetals with strong electrostatic forces. NaCl is a classic ionic compound.

Correct Answer: (B)


Exercise 8

Which of the following statements best explains why metallic solids are good conductors of electricity?

  • (A) They have high lattice energies.
  • (B) Their electrons are localized and tightly bound to individual atoms.
  • (C) They consist of a lattice of cations surrounded by a sea of delocalized electrons.
  • (D) They form discrete molecules with strong intermolecular forces.
해답 보기

Answer Explanation:

Metallic solids have delocalized electrons that move freely through the lattice, enabling good electrical conductivity.

Correct Answer: (C)


Exercise 9

During a chemical reaction, bond breaking requires energy input while bond forming releases energy. Which scenario is correct?

  • (A) Breaking a covalent bond in methane is exothermic; forming an ionic bond in NaCl is endothermic.
  • (B) Breaking an ionic bond in NaCl is endothermic; forming a metallic bond in Cu is exothermic.
  • (C) Breaking a metallic bond in Fe is exothermic; forming a covalent bond in H2O is endothermic.
  • (D) Breaking a hydrogen bond in H2O is exothermic; forming a covalent bond in CO2 is exothermic.
View Answer

Answer Explanation:

Bond breaking is endothermic, bond forming is exothermic. Option (B) is correct: Breaking ionic bond in NaCl = endothermic, forming metallic bond in Cu = exothermic.

Correct Answer: (B)


Exercise 10

Compare the bond strength of Lithium Fluoride (LiF) and Sodium Chloride (NaCl). Which compound has a stronger ionic bond and why?

  • (A) LiF has a stronger ionic bond because Li+ and F have higher charges than Na+ and Cl.
  • (B) NaCl has a stronger ionic bond because Na+ and Cl are larger ions.
  • (C) LiF has a stronger ionic bond due to smaller ionic radii and higher charge density.
  • (D) Both have similar bond strengths.
해답 보기

LiF has smaller ions, hence greater charge density and stronger electrostatic attraction.

Correct Answer: (C)


Exercise 11

Which molecular geometry corresponds to a molecule with two bonding pairs and two lone pairs on the central atom?

  • (A) Linear
  • (B) Trigonal Planar
  • (C) Tetrahedral
  • (D) Bent
해답 보기

Two bonding pairs + two lone pairs → Bent geometry (like H2O).

Correct Answer: (D)


Exercise 12

Which of the following molecules has sp3 hybridization at the central atom?

  • (A) CO2
  • (B) BF3
  • (C) CH4
  • (D) SO3
해답 보기

CH4 (methane) is sp3 with four bonding pairs on carbon.

Correct Answer: (C)


Exercise 13

Which of the following molecules has a see-saw molecular geometry?

  • (A) SF4
  • (B) PF5
  • (C) XeF4
  • (D) BF3
View Answer

SF4 is see-saw (4 bonds, 1 lone pair on sulfur).

Correct Answer: (A)


Exercise 14

Which of the following best explains why covalent crystals like diamond have very high melting points?

  • (A) They consist of discrete molecules with weak IMF.
  • (B) They have a continuous network of strong covalent bonds.
  • (C) They contain delocalized electrons that facilitate metallic bonding.
  • (D) They are composed of ions held by electrostatic forces.
해답 보기

Covalent crystals have a continuous network of strong covalent bonds (e.g., diamond).

Correct Answer: (B)


Exercise 15

Which of the following properties is most characteristic of metallic bonding in a substance?

  • (A) High electrical conductivity in both solid and liquid states.
  • (B) High melting point but poor conductivity in solids.
  • (C) Low melting point and discrete molecules.
  • (D) Solubility in polar solvents like water.
View Answer

Metallic bonding is characterized by free electrons conduction in solids and liquids.

Correct Answer: (A)


Exercise 16

Which of the following molecules exhibits hydrogen bonding?

  • (A) CH4
  • (B) H2S
  • (C) NH3
  • (D) CO2
해답 보기

NH3 forms hydrogen bonds (N—H with a lone pair on N).

Correct Answer: (C)


Exercise 17

Explain why Lithium (Li) has a stronger metallic bond compared to Sodium (Na).

  • (A) Li has more delocalized electrons.
  • (B) Li atoms are larger, so stronger attraction.
  • (C) Li has a higher effective nuclear charge, pulling electrons more strongly.
  • (D) Li forms interstitial alloys more readily.
해답 보기

Because Li is smaller and has a higher effective nuclear charge, it holds its electron sea more tightly, strengthening the metallic bond.

Correct Answer: (C)


Exercise 18

Which of the following substances is expected to conduct electricity in its solid state?

  • (A) Diamond (C)
  • (B) Sodium Chloride (NaCl)
  • (C) Graphite (C)
  • (D) Ice (H2O)
해답 보기

Graphite conducts in solid state due to delocalized electrons in planes.

Correct Answer: (C)


Exercise 19

Which type of molecular geometry is associated with a molecule that has three bonding pairs and one lone pair on the central atom?

  • (A) Tetrahedral
  • (B) Trigonal Pyramidal
  • (C) Bent
  • (D) Trigonal Planar
해답 보기

3 bonding + 1 lone → Trigonal pyramidal (like NH3).

Correct Answer: (B)


Exercise 20

Which of the following substances is an example of a network covalent solid, with very high melting point and hardness?

  • (A) Sodium Chloride (NaCl)
  • (B) Graphite (C)
  • (C) Methane (CH4)
  • (D) Magnesium (Mg)
View Answer

Graphite is a network covalent solid (so is diamond). Option (B).

Correct Answer: (B)


Exercise 21

Which molecular geometry has bond angles of ~109.5°?

  • (A) Linear
  • (B) Trigonal Planar
  • (C) Tetrahedral
  • (D) Bent
해답 보기

Tetrahedral geometry has ~109.5° angles.

Correct Answer: (C)


Exercise 22

In the formation of an ionic bond between Mg and O, which is correct?

  • (A) Mg gains 2 e⁻, O loses 2 e⁻
  • (B) Mg loses 2 e⁻, O gains 2 e⁻
  • (C) Mg gains 1 e⁻, O loses 1 e⁻
  • (D) Mg shares 2 e⁻ with O
해답 보기

Mg → Mg2+, O → O2-. So Mg loses 2, O gains 2.

Correct Answer: (B)


Exercise 23

During numbering, we see a mismatch, but continuing: Which statement about bond length & bond strength is correct?

  • (A) Shorter bond lengths → weaker bonds
  • (B) Longer bond lengths → stronger bonds
  • (C) Shorter bond lengths → stronger bonds
  • (D) Bond length & strength are independent
해답 보기

Shorter bonds are typically stronger.

Correct Answer: (C)


Exercise 24

Which type of IMF primarily accounts for water’s high boiling point?

  • (A) London dispersion
  • (B) Dipole-dipole
  • (C) Hydrogen bonding
  • (D) Ionic bonding
해답 보기

Water’s high boiling point is due to hydrogen bonds.

Correct Answer: (C)


Exercise 25

Why can graphite conduct electricity while diamond cannot?

  • (A) Graphite has discrete molecules; diamond has network bonds.
  • (B) Graphite has delocalized electrons; diamond does not.
  • (C) Diamond has higher lattice energy than graphite.
  • (D) Graphite forms ionic bonds; diamond forms covalent bonds.
해답 보기

Graphite has delocalized electrons in planar sheets, allowing conduction. Diamond lacks them.

Correct Answer: (B)


Exercise 26

What explains the difference in hardness between diamond & graphite?

  • (A) Diamond is layered; graphite is tetrahedral.
  • (B) Diamond has strong 3D covalent bonds; graphite has strong in-layer but weak interlayer forces.
  • (C) Graphite has stronger IMF than diamond.
  • (D) Graphite has a higher lattice energy than diamond.
해답 보기

Diamond is a 3D network covalent solid, very hard. Graphite has layered structure (weak forces between layers).

Correct Answer: (B)


Exercise 27

Why do ionic solids typically have higher melting points than molecular solids?

  • (A) Ionic solids have weaker forces.
  • (B) Ionic solids have strong electrostatic attractions.
  • (C) Molecular solids have a continuous covalent network.
  • (D) Molecular solids contain delocalized electrons.
해답 보기

Ionic solids are held by strong electrostatic forces between ions.

Correct Answer: (B)


Exercise 28

According to Coulomb’s Law, which factor does NOT directly affect ionic bond strength?

  • (A) The charges on the ions
  • (B) The distance between ions
  • (C) The number of valence electrons (outer electrons) per se
  • (D) The types of ions (which affects charge/radius)
View Answer

Coulomb’s Law depends on charge magnitude (q1q2) and distance (r), not directly the total # of valence electrons apart from how they form the ions.

Correct Answer: (C)


Exercise 29

Which compound contains both ionic and covalent bonds?

  • (A) NaCl
  • (B) CO2
  • (C) NH4NO3
  • (D) CH4
View Answer

Ammonium nitrate has ionic bonding between NH4+ and NO3, plus covalent bonds within those ions.

Correct Answer: (C)


Exercise 30

Which best explains why water (H2O) has a higher boiling point than hydrogen sulfide (H2S)?

  • (A) H2O has stronger hydrogen bonding.
  • (B) H2S has more polar bonds.
  • (C) H2O has weaker IMF.
  • (D) H2S is a network covalent solid.
해답 보기

Water forms strong hydrogen bonds; H2S does not.

Correct Answer: (A)


Exercise 31

Which explains why magnesium (Mg) has a stronger metallic bond than lithium (Li)?

  • (A) Mg has more delocalized electrons (2 vs 1).
  • (B) Mg is larger, so stronger bond.
  • (C) Mg has higher ionization energy.
  • (D) Mg has lower electronegativity.
해답 보기

Magnesium can contribute two electrons to the “sea”, strengthening the metallic bond.

Correct Answer: (A)


Exercise 32

Based on Coulomb’s Law, which ionic compound has the greatest lattice energy?

  • (A) CaO
  • (B) AlN
  • (C) SrS
  • (D) KF
View Answer

AlN with Al3+ and N3- yields higher charge product and smaller ions → highest lattice energy.

Correct Answer: (B)


Exercise 33

Which molecular geometry corresponds to sp3 hybridization and one lone pair?

  • (A) Trigonal Planar
  • (B) Tetrahedral
  • (C) Trigonal Pyramidal
  • (D) Linear
해답 보기

sp3 with 1 lone pair → trigonal pyramidal (like NH3).

Correct Answer: (C)


Exercise 34

Why is silicon (Si) classified as a network covalent solid rather than a molecular solid?

  • (A) Si forms discrete Si4 molecules.
  • (B) Si forms a 3D network of covalent bonds.
  • (C) Si has delocalized electrons like metals.
  • (D) Si exists as isolated atoms.
해답 보기

Silicon has a continuous 3D covalent network (like diamond).

Correct Answer: (B)


Exercise 35

Which statement about bond energy & bond length is accurate?

  • (A) Triple bonds are longer/weaker than single bonds.
  • (B) Double bonds are longer than single but lower bond energy.
  • (C) More shared pairs → shorter bond length & higher bond energy.
  • (D) All have same bond energy.
해답 보기

Increasing shared pairs = shorter length & stronger bond.

Correct Answer: (C)


Exercise 36

Which statement distinguishes interstitial vs. substitutional alloys?

  • (A) Interstitial: similar-size atoms replace each other; Substitutional: smaller fill holes.
  • (B) Substitutional: different-size fill holes; Interstitial: similar-size replace.
  • (C) Interstitial: different-size fill holes; Substitutional: comparable radii replace.
  • (D) Both exclusively have similar radii atoms.
해답 보기

Interstitial = smaller atoms filling holes; Substitutional = similar-size atoms replacing some metal atoms.

Correct Answer: (C)


Exercise 37

Arrange in order of highest to lowest lattice energy: MgO, LiF, NaCl, KBr.

  • (A) MgO > LiF > NaCl > KBr
  • (B) LiF > MgO > NaCl > KBr
  • (C) NaCl > MgO > LiF > KBr
  • (D) KBr > NaCl > LiF > MgO
해답 보기

MgO has highest (2+/2-), then LiF (small ions), then NaCl, then KBr.

Correct Answer: (A)


Exercise 38

Which molecule exhibits resonance due to delocalized electrons?

  • (A) CH4
  • (B) C2H6
  • (C) C6H6 (Benzene)
  • (D) CCl4
해답 보기

Benzene has resonance among ring double bonds.

Correct Answer: (C)


Exercise 39

How does bond polarity relate to molecular polarity?

  • (A) All molecules with polar bonds are polar.
  • (B) A molecule can be nonpolar even if it has polar bonds.
  • (C) Molecules with nonpolar bonds are always polar.
  • (D) Molecular polarity is unrelated to bond polarity.
View Answer

Dipoles can cancel if geometry is symmetrical. So a molecule with polar bonds can be nonpolar overall.

Correct Answer: (B)


Exercise 40

Which molecule has a trigonal pyramidal geometry and is polar due to a lone pair on the central atom?

  • (A) CCl4
  • (B) NH3
  • (C) BF3
  • (D) H2O
View Answer

NH3 is trigonal pyramidal (3 bonds, 1 lone pair) and polar.

Correct Answer: (B)


Exercise 41

Which ion exhibits resonance due to delocalized electrons?

  • (A) NH4+
  • (B) SO42-
  • (C) OH
  • (D) Na+
View Answer

Sulfate (SO4 2-) has resonance among the S=O bonds.

Correct Answer: (B)


Exercise 42

Which best explains HF’s higher boiling point vs. other hydrogen halides (HCl, HBr, HI)?

  • (A) HF has stronger London dispersion forces.
  • (B) HF forms ionic bonds due to less shielding.
  • (C) HF forms strong hydrogen bonds via highly electronegative F.
  • (D) HF is smaller, enabling closer packing.
View Answer

HF has strong hydrogen bonding, whereas HCl/HBr/HI rely on weaker dipole or dispersion.

Correct Answer: (C)


Exercise 43

Which molecule is nonpolar yet has polar bonds?

  • (A) H2O
  • (B) CO2
  • (C) NH3
  • (D) HF
View Answer

CO2 is linear with bond dipoles canceling out, making it nonpolar.

Correct Answer: (B)


Exercise 44

Which molecular geometry has the highest number of electron pairs around the central atom?

  • (A) Linear
  • (B) Trigonal Planar
  • (C) Tetrahedral
  • (D) Octahedral
View Answer

Octahedral has six electron pairs around the center.

Correct Answer: (D)


Exercise 45

Why does diamond have a higher melting point than O2?

  • (A) Diamond has stronger hydrogen bonds.
  • (B) Diamond is a 3D network solid; O2 is just molecular with weak intermolecular forces.
  • (C) O2 has heavier molecular weight.
  • (D) Diamond has delocalized electrons.
View Answer

Diamond is a network covalent solid, very strong bonds. O2 has weak IMF.

Correct Answer: (B)


Exercise 46

Why do molecular solids generally have lower melting points than ionic solids?

  • (A) Molecular solids have stronger covalent bonds between molecules.
  • (B) Molecular solids have weaker intermolecular forces vs. strong ionic bonds.
  • (C) Ionic solids have larger ions.
  • (D) Ionic solids do not conduct electricity.
View Answer

Molecular solids rely on weaker IMF, while ionic solids have strong electrostatic attractions.

Correct Answer: (B)


Exercise 47

Which statement about network covalent solids and their conductivity is correct?

  • (A) Diamond conducts electricity as all electrons are free.
  • (B) Silicon is a conductor at room temp. due to free electrons.
  • (C) Graphite conducts (delocalized electrons), silicon & SiO2 do not.
  • (D) SiO2 conducts electricity due to a regular lattice.
View Answer

Graphite is unique among network covalents in that it conducts electricity via delocalized electrons. Diamond, Si, SiO2 do not.

Correct Answer: (C)


Exercise 48

According to VSEPR, what is the geometry of SO2?

  • (A) Linear
  • (B) Trigonal Planar
  • (C) Trigonal Pyramidal
  • (D) Bent
해답 보기

SO2 has 2 bonding pairs + 1 lone pair → Bent geometry.

Correct Answer: (D)


Exercise 49

Which hybridization is associated with trigonal bipyramidal geometry?

  • (A) sp
  • (B) sp2
  • (C) sp3
  • (D) sp3d
View Answer

Trigonal bipyramidal → sp3d.

Correct Answer: (D)


Exercise 50

Which molecule has the lowest boiling point and why?

  • (A) H2O
  • (B) CH3OH (Methanol)
  • (C) H2S
  • (D) NH3
View Answer

H2S has weaker H-bonding or dipoles than H2O, CH3OH, NH3.

Correct Answer: (C)


Exercise 51

Which best describes the role of delocalized electrons in metallic bonding?

  • (A) They form covalent bonds.
  • (B) They localize between cations.
  • (C) They move freely, allowing electrical conductivity.
  • (D) They form ionic bonds.
View Answer

Delocalized electrons in metals roam freely, enabling conductivity.

Correct Answer: (C)


Exercise 52

Which molecule is expected to have the greatest bond polarity?

  • (A) Cl2
  • (B) H2O
  • (C) CO2
  • (D) HF
View Answer

HF has the largest electronegativity difference (H-F).

Correct Answer: (D)


Exercise 53

Which statement is true about network covalent solids vs. molecular solids?

  • (A) Network covalents have lower melting points.
  • (B) Network covalents are typically soft & brittle.
  • (C) Network covalents do not conduct electricity (generally).
  • (D) Network covalents have strong bonding throughout the structure.
View Answer

They have strong covalent bonds throughout, leading to high melting points, hardness, etc.

Correct Answer: (D)


Exercise 54

Which compound is expected to conduct electricity in the solid state?

  • (A) Diamond (C)
  • (B) Silicon dioxide (SiO2)
  • (C) Graphite (C)
  • (D) Sodium chloride (NaCl)
View Answer

Graphite can conduct as a solid. The others cannot (diamond, SiO2 do not conduct, NaCl is ionic—only in molten or aqueous form).

Correct Answer: (C)


Exercise 55

Which molecule is nonpolar despite having polar bonds?

  • (A) HCl
  • (B) CO2
  • (C) NH3
  • (D) HF
View Answer

CO2 is linear and dipoles cancel, so it is nonpolar.

Correct Answer: (B)


Exercise 56

Which best describes the hybridization of C in methane (CH4)?

  • (A) sp
  • (B) sp2
  • (C) sp3
  • (D) dsp3
View Answer

CH4 is tetrahedral → sp3.

Correct Answer: (C)


Exercise 57

Which compound primarily exhibits London dispersion forces in the liquid state?

  • (A) H2O
  • (B) CH4
  • (C) NH3
  • (D) HF
View Answer

CH4 is nonpolar, so only London dispersion forces.

Correct Answer: (B)


Exercise 58

Which molecule exhibits trigonal planar geometry?

  • (A) CH4
  • (B) NH3
  • (C) BF3
  • (D) H2O
View Answer

BF3 has 3 bonds, no lone pairs on B → trigonal planar.

Correct Answer: (C)


Exercise 59

Why do network covalent solids generally have higher melting points than molecular solids?

  • (A) Network covalents have stronger IMFs.
  • (B) They have extensive covalent bonds throughout the structure.
  • (C) Molecular solids have bigger molecules with weaker bonds.
  • (D) Molecular solids have delocalized electrons, making them easier to melt.
View Answer

Network covalent = strong covalent network, not just IMFs.

Correct Answer: (B)


Exercise 60

Which molecule has a square planar geometry?

  • (A) XeF4
  • (B) SF4
  • (C) PF5
  • (D) ClF3
View Answer

XeF4 is square planar (4 bonds, 2 lone pairs on Xe).

Correct Answer: (A)


Exercise 61

Which molecule would have the strongest dipole-dipole interactions in liquid state?

  • (A) CCl4
  • (B) NH3
  • (C) SF6
  • (D) CH4
View Answer

NH3 is polar with hydrogen bonding. Others are either nonpolar or less polar.

Correct Answer: (B)


Exercise 62

Why does NH3 have a higher boiling point than CH4?

  • (A) NH3 has a larger mol. weight.
  • (B) NH3 forms hydrogen bonds; CH4 has only dispersion.
  • (C) CH4 is polar, NH3 is nonpolar.
  • (D) NH3 has a symmetrical shape.
해답 보기

Ammonia forms H-bonds; methane does not → higher boiling point.

Correct Answer: (B)


Exercise 63

Which bonding type is responsible for the high melting point & hardness of diamond?

  • (A) Metallic
  • (B) Ionic
  • (C) Covalent network
  • (D) Van der Waals
View Answer

Diamond is a covalent network solid (sp3-bonded carbon network).

Correct Answer: (C)


Exercise 64

Which best explains why HF has a higher boiling point than HCl?

  • (A) HF has stronger hydrogen bonding due to F’s electronegativity.
  • (B) HCl has stronger dipoles.
  • (C) HF has bigger molecules.
  • (D) HCl forms a network covalent structure.
View Answer

Fluorine is highly electronegative → strong H-bonding in HF.

Correct Answer: (A)


Exercise 65

Which molecule is linear due to sp hybridization?

  • (A) BeCl2
  • (B) SO2
  • (C) NH3
  • (D) H2O
View Answer

BeCl2 is sp & linear (2 bonds, no lone pairs on Be).

Correct Answer: (A)


Exercise 66

Which molecule exhibits hydrogen bonding in the liquid state?

  • (A) H2S
  • (B) CH4
  • (C) C2H5OH (Ethanol)
  • (D) CCl4
해답 보기
Ethanol has an -OH group, enabling hydrogen bonding.
Correct Answer: (C)

Exercise 67

Why does MgO have a higher lattice energy than NaCl?

  • (A) MgO has bigger ions.
  • (B) MgO has ions with higher charges.
  • (C) NaCl has higher charge density.
  • (D) NaCl forms stronger metallic bonds.
View Answer

Mg2+ and O2- → larger charge product than Na+, Cl.

Correct Answer: (B)


Exercise 68

Which molecule has a see-saw geometry due to one lone pair on the central atom?

  • (A) SF4
  • (B) PCl5
  • (C) ClF3
  • (D) XeF2
View Answer
SF4 has 4 bonding pairs, 1 lone pair → see-saw.
Correct Answer: (A)

Exercise 69

Which statement about geometry & hybridization is correct?

  • (A) All linear molecules have sp3.
  • (B) Tetrahedral molecules have sp3.
  • (C) Trigonal pyramidal molecules have sp2.
  • (D) Bent molecules have sp.
View Answer

Tetrahedral → sp3 (e.g. CH4).

Correct Answer: (B)


Exercise 70

Why does SiO2 have a high melting point?

  • (A) Discrete molecules with strong H-bonds.
  • (B) Continuous 3D network of strong covalent bonds.
  • (C) Ionic bonds between Si4+ and O2-.
  • (D) Metallic bonding with delocalized electrons.
View Answer

SiO2 is a network covalent solid (like quartz) with high melting point.

Correct Answer: (B)


Exercise 71

Why can metals like Cu conduct electricity, but nonmetals like S cannot?

  • (A) Metals have free electrons, nonmetals do not.
  • (B) Nonmetals have more protons blocking electrons.
  • (C) Metals form ionic bonds, allowing electron flow.
  • (D) Nonmetals have delocalized electrons that block conduction.
View Answer

Metals have a “sea of electrons” that move freely; nonmetals lack such delocalized electrons.

Correct Answer: (A)


Exercise 72

Why do ionic bonds typically result in high melting and boiling points?

  • (A) Ionic bonds involve shared electrons (covalent).
  • (B) Strong electrostatic attraction between ions requires lots of energy to break.
  • (C) Delocalized electrons enhance ionic bonding.
  • (D) Ionic bonds are weaker than metallic bonds.
View Answer

Ionic bonds are strong electrostatic forces; large energy is needed to break the lattice.

Correct Answer: (B)


Exercise 73

Which best describes the intermolecular forces in SiO2?

  • (A) Hydrogen bonds
  • (B) Dipole-dipole
  • (C) London dispersion
  • (D) Network covalent bonds
View Answer

SiO2 is a network solid with covalent bonds, not “intermolecular” forces in the typical sense.

Correct Answer: (D)


Exercise 74

Which molecule exhibits a net dipole moment?

  • (A) CO2
  • (B) BF3
  • (C) NH3
  • (D) C2H6
View Answer

NH3 has a trigonal pyramidal shape, net dipole. CO2, BF3 are symmetrical, C2H6 is also nonpolar.

Correct Answer: (C)


Exercise 75

Which statement about ionic solids is correct?

  • (A) Good conductors in solid state.
  • (B) Low melting points due to weak forces.
  • (C) They are brittle and shatter under force.
  • (D) They are malleable like metals.
View Answer

Ionic solids are brittle, not malleable, have high melting points, and do not conduct as solids.

Correct Answer: (C)


Exercise 76

Which molecule is nonpolar due to its symmetrical geometry despite polar bonds?

  • (A) H2O
  • (B) CCl4
  • (C) NH3
  • (D) HF
View Answer
CCl4 is tetrahedral, each C-Cl bond is polar but net dipole = 0
Correct Answer: (B)

Exercise 77

Why are hydrogen bonds stronger than London dispersion forces?

  • (A) H-bonds involve full electron sharing (covalent).
  • (B) H-bonds occur with highly electronegative atoms (N, O, F) creating strong dipoles.
  • (C) London forces are a type of hydrogen bond.
  • (D) H-bonds are weaker than dipole-dipole.
View Answer

Hydrogen bonding is a special, stronger form of dipole-dipole with high electronegativity differences.

Correct Answer: (B)


Exercise 78

Which molecule exhibits sp3 hybridization at the central atom?

  • (A) CO2
  • (B) NH3
  • (C) BF3
  • (D) XeF4
해답 보기

NH3 is sp3.

Correct Answer: (B)


Exercise 79

Which network covalent solid has a layered structure, making it soft & slippery?

  • (A) Diamond
  • (B) Silicon
  • (C) Graphite
  • (D) Silicon dioxide
View Answer

Graphite is layered carbon, easily sheared.

Correct Answer: (C)


Exercise 80

Which of the following best explains why network covalent solids like diamond and silicon dioxide do not conduct electricity?

Options:

  • (A) They lack delocalized electrons.
  • (B) They have high lattice energies.
  • (C) They have symmetrical molecular geometries.
  • (D) They possess lone pairs of electrons.
View Answer

Answer Explanation:

Network covalent solids like diamond and silicon dioxide have all their electrons involved in strong covalent bonds, leaving no delocalized electrons available to conduct electricity.

Correct Answer: (A) They lack delocalized electrons.


Exercise 81

Which of the following best describes the process of bond formation in covalent bonds?

Options:

  • (A) Electrons are transferred from one atom to another.
  • (B) Electrons are shared between two atoms.
  • (C) Electrons become delocalized over a metal lattice.
  • (D) Electrons are removed entirely from a molecule.
View Answer

Answer Explanation:

Covalent bonds form when two atoms share electrons to achieve stable electron configurations. This differs from ionic bonds (electron transfer) or metallic bonds (delocalized electrons).

Correct Answer: (B) Electrons are shared between two atoms.


Exercise 82

Which of the following statements correctly describes the relationship between bond energy and potential energy during bond formation?

Options:

  • (A) Bond energy decreases as potential energy decreases.
  • (B) Bond energy is inversely related to potential energy.
  • (C) Bond energy is directly proportional to the difference in potential energy before and after bond formation.
  • (D) Bond energy and potential energy are unrelated concepts.
View Answer

Answer Explanation:

The bond energy (or bond dissociation energy) corresponds to the difference in potential energy between separated atoms and bonded atoms. A larger difference means a higher bond energy.

Correct Answer: (C)


Exercise 83

Which of the following best explains why methane (CH4) has a tetrahedral geometry?

Options:

  • (A) It has sp2 hybridization.
  • (B) It has sp3 hybridization with no lone pairs.
  • (C) It has sp hybridization with two lone pairs.
  • (D) It has dsp3 hybridization.
View Answer

Answer Explanation:

In CH4, carbon forms four sp3-hybrid orbitals, each bonding to a hydrogen. No lone pairs remain on carbon, resulting in a tetrahedral shape (~109.5°).

Correct Answer: (B)


Exercise 84

Which of the following best describes the trend in bond strength among the hydrogen halides: HF, HCl, HBr, and HI?

Options:

  • (A) HF > HCl > HBr > HI
  • (B) HI > HBr > HCl > HF
  • (C) HCl > HF > HI > HBr
  • (D) HBr > HI > HF > HCl
View Answer

Answer Explanation:

As halide atoms increase in size (Cl → Br → I), bond length increases and bond strength decreases. HF is the shortest and strongest, then HCl, HBr, and finally HI as the weakest.

Correct Answer: (A)


Exercise 85

Which of the following best explains why hydrogen sulfide (H2S) has a lower boiling point than hydrogen peroxide (H2O2)?

Options:

  • (A) H2S has stronger hydrogen bonds than H2O2.
  • (B) H2O2 has stronger hydrogen bonds due to additional hydroxyl groups.
  • (C) H2S is a larger molecule, resulting in weaker intermolecular forces.
  • (D) H2O2 has a lower molecular weight, leading to a lower boiling point.
View Answer

Answer Explanation:

Hydrogen peroxide (H2O2) can form more extensive hydrogen bonding because it has two —OH groups, resulting in stronger intermolecular forces and a higher boiling point than H2S (which cannot form such strong hydrogen bonds).

Correct Answer: (B)


Exercise 86

Which of the following best explains the difference in electrical conductivity between metallic solids and molecular solids?

Options:

  • (A) Metallic solids have delocalized electrons that can move freely, while molecular solids do not.
  • (B) Molecular solids have delocalized electrons, while metallic solids do not.
  • (C) Both metallic and molecular solids have delocalized electrons, but molecular solids have stronger bonds.
  • (D) Neither metallic nor molecular solids have delocalized electrons.
View Answer

Answer Explanation:

Metals have a “sea of electrons” free to move throughout the lattice, enabling conductivity. Molecular solids, composed of discrete molecules with localized electrons, generally cannot conduct electricity in the solid state.

Correct Answer: (A)


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