Exercise 1
Boron Trifluoride (BF3)
Task: Determine the molecular geometry and hybridization.
해답 보기
Answer Explanation:
BF3 has a trigonal planar geometry with sp2 hybridization. Boron has three bonding pairs and no lone pairs.
Correct Answer: Trigonal Planar, sp2
Exercise 2
Phosphorus Trichloride (PCl3)
Task: Determine the molecular geometry and hybridization.
해답 보기
Answer Explanation:
PCl3 has a trigonal pyramidal geometry with sp3 hybridization. Phosphorus has three bonding pairs and one lone pair.
Correct Answer: Trigonal Pyramidal, sp3
Exercise 3
Triiodide Ion (I3–)
Task: Determine the molecular geometry and hybridization.
해답 보기
Answer Explanation:
I3– has a linear geometry with sp3d hybridization. The central iodine has two bonding pairs and three lone pairs.
Correct Answer: Linear, sp3d
Exercise 4
Nitrite Ion (NO2–)
Task: Determine the molecular geometry and hybridization.
해답 보기
Answer Explanation:
NO2– has a bent geometry with sp2 hybridization. Nitrogen has two bonding pairs and one lone pair.
Correct Answer: Bent, sp2
Exercise 5
Nitrate Ion (NO3–)
Task: Determine the molecular geometry and hybridization.
해답 보기
Answer Explanation:
NO3– has a trigonal planar geometry with sp2 hybridization. Nitrogen has three bonding pairs and no lone pairs.
Correct Answer: Trigonal Planar, sp2
Exercise 6
Which of the following compounds has the highest lattice energy?
- (A) Sodium Chloride (NaCl)
- (B) Lithium Fluoride (LiF)
- (C) Magnesium Oxide (MgO)
- (D) Potassium Bromide (KBr)
해답 보기
Answer Explanation:
Lattice energy increases with higher charges on the ions and smaller ionic radii. Magnesium oxide (MgO) has Mg2+ and O2-, so it has a higher lattice energy than the other compounds.
Correct Answer: (C) MgO
Exercise 7
Which of the following substances is most likely to form an ionic bond based on its properties?
- (A) Gold (Au)
- (B) Sodium Chloride (NaCl)
- (C) Methane (CH4)
- (D) Carbon Dioxide (CO2)
View Answer
Answer Explanation:
Ionic bonds typically form between metals and nonmetals with strong electrostatic forces. NaCl is a classic ionic compound.
Correct Answer: (B)
Exercise 8
Which of the following statements best explains why metallic solids are good conductors of electricity?
- (A) They have high lattice energies.
- (B) Their electrons are localized and tightly bound to individual atoms.
- (C) They consist of a lattice of cations surrounded by a sea of delocalized electrons.
- (D) They form discrete molecules with strong intermolecular forces.
해답 보기
Answer Explanation:
Metallic solids have delocalized electrons that move freely through the lattice, enabling good electrical conductivity.
Correct Answer: (C)
Exercise 9
During a chemical reaction, bond breaking requires energy input while bond forming releases energy. Which scenario is correct?
- (A) Breaking a covalent bond in methane is exothermic; forming an ionic bond in NaCl is endothermic.
- (B) Breaking an ionic bond in NaCl is endothermic; forming a metallic bond in Cu is exothermic.
- (C) Breaking a metallic bond in Fe is exothermic; forming a covalent bond in H2O is endothermic.
- (D) Breaking a hydrogen bond in H2O is exothermic; forming a covalent bond in CO2 is exothermic.
View Answer
Answer Explanation:
Bond breaking is endothermic, bond forming is exothermic. Option (B) is correct: Breaking ionic bond in NaCl = endothermic, forming metallic bond in Cu = exothermic.
Correct Answer: (B)
Exercise 10
Compare the bond strength of Lithium Fluoride (LiF) and Sodium Chloride (NaCl). Which compound has a stronger ionic bond and why?
- (A) LiF has a stronger ionic bond because Li+ and F– have higher charges than Na+ and Cl–.
- (B) NaCl has a stronger ionic bond because Na+ and Cl– are larger ions.
- (C) LiF has a stronger ionic bond due to smaller ionic radii and higher charge density.
- (D) Both have similar bond strengths.
해답 보기
LiF has smaller ions, hence greater charge density and stronger electrostatic attraction.
Correct Answer: (C)
Exercise 11
Which molecular geometry corresponds to a molecule with two bonding pairs and two lone pairs on the central atom?
- (A) Linear
- (B) Trigonal Planar
- (C) Tetrahedral
- (D) Bent
해답 보기
Two bonding pairs + two lone pairs → Bent geometry (like H2O).
Correct Answer: (D)
Exercise 12
Which of the following molecules has sp3 hybridization at the central atom?
- (A) CO2
- (B) BF3
- (C) CH4
- (D) SO3
해답 보기
CH4 (methane) is sp3 with four bonding pairs on carbon.
Correct Answer: (C)
Exercise 13
Which of the following molecules has a see-saw molecular geometry?
- (A) SF4
- (B) PF5
- (C) XeF4
- (D) BF3
View Answer
SF4 is see-saw (4 bonds, 1 lone pair on sulfur).
Correct Answer: (A)
Exercise 14
Which of the following best explains why covalent crystals like diamond have very high melting points?
- (A) They consist of discrete molecules with weak IMF.
- (B) They have a continuous network of strong covalent bonds.
- (C) They contain delocalized electrons that facilitate metallic bonding.
- (D) They are composed of ions held by electrostatic forces.
해답 보기
Covalent crystals have a continuous network of strong covalent bonds (e.g., diamond).
Correct Answer: (B)
Exercise 15
Which of the following properties is most characteristic of metallic bonding in a substance?
- (A) High electrical conductivity in both solid and liquid states.
- (B) High melting point but poor conductivity in solids.
- (C) Low melting point and discrete molecules.
- (D) Solubility in polar solvents like water.
View Answer
Metallic bonding is characterized by free electrons conduction in solids and liquids.
Correct Answer: (A)
Exercise 16
Which of the following molecules exhibits hydrogen bonding?
- (A) CH4
- (B) H2S
- (C) NH3
- (D) CO2
해답 보기
NH3 forms hydrogen bonds (N—H with a lone pair on N).
Correct Answer: (C)
Exercise 17
Explain why Lithium (Li) has a stronger metallic bond compared to Sodium (Na).
- (A) Li has more delocalized electrons.
- (B) Li atoms are larger, so stronger attraction.
- (C) Li has a higher effective nuclear charge, pulling electrons more strongly.
- (D) Li forms interstitial alloys more readily.
해답 보기
Because Li is smaller and has a higher effective nuclear charge, it holds its electron sea more tightly, strengthening the metallic bond.
Correct Answer: (C)
Exercise 18
Which of the following substances is expected to conduct electricity in its solid state?
- (A) Diamond (C)
- (B) Sodium Chloride (NaCl)
- (C) Graphite (C)
- (D) Ice (H2O)
해답 보기
Graphite conducts in solid state due to delocalized electrons in planes.
Correct Answer: (C)
Exercise 19
Which type of molecular geometry is associated with a molecule that has three bonding pairs and one lone pair on the central atom?
- (A) Tetrahedral
- (B) Trigonal Pyramidal
- (C) Bent
- (D) Trigonal Planar
해답 보기
3 bonding + 1 lone → Trigonal pyramidal (like NH3).
Correct Answer: (B)
Exercise 20
Which of the following substances is an example of a network covalent solid, with very high melting point and hardness?
- (A) Sodium Chloride (NaCl)
- (B) Graphite (C)
- (C) Methane (CH4)
- (D) Magnesium (Mg)
View Answer
Graphite is a network covalent solid (so is diamond). Option (B).
Correct Answer: (B)
Exercise 21
Which molecular geometry has bond angles of ~109.5°?
- (A) Linear
- (B) Trigonal Planar
- (C) Tetrahedral
- (D) Bent
해답 보기
Tetrahedral geometry has ~109.5° angles.
Correct Answer: (C)
Exercise 22
In the formation of an ionic bond between Mg and O, which is correct?
- (A) Mg gains 2 e⁻, O loses 2 e⁻
- (B) Mg loses 2 e⁻, O gains 2 e⁻
- (C) Mg gains 1 e⁻, O loses 1 e⁻
- (D) Mg shares 2 e⁻ with O
해답 보기
Mg → Mg2+, O → O2-. So Mg loses 2, O gains 2.
Correct Answer: (B)
Exercise 23
During numbering, we see a mismatch, but continuing: Which statement about bond length & bond strength is correct?
- (A) Shorter bond lengths → weaker bonds
- (B) Longer bond lengths → stronger bonds
- (C) Shorter bond lengths → stronger bonds
- (D) Bond length & strength are independent
해답 보기
Shorter bonds are typically stronger.
Correct Answer: (C)
Exercise 24
Which type of IMF primarily accounts for water’s high boiling point?
- (A) London dispersion
- (B) Dipole-dipole
- (C) Hydrogen bonding
- (D) Ionic bonding
해답 보기
Water’s high boiling point is due to hydrogen bonds.
Correct Answer: (C)
Exercise 25
Why can graphite conduct electricity while diamond cannot?
- (A) Graphite has discrete molecules; diamond has network bonds.
- (B) Graphite has delocalized electrons; diamond does not.
- (C) Diamond has higher lattice energy than graphite.
- (D) Graphite forms ionic bonds; diamond forms covalent bonds.
해답 보기
Graphite has delocalized electrons in planar sheets, allowing conduction. Diamond lacks them.
Correct Answer: (B)
Exercise 26
What explains the difference in hardness between diamond & graphite?
- (A) Diamond is layered; graphite is tetrahedral.
- (B) Diamond has strong 3D covalent bonds; graphite has strong in-layer but weak interlayer forces.
- (C) Graphite has stronger IMF than diamond.
- (D) Graphite has a higher lattice energy than diamond.
해답 보기
Diamond is a 3D network covalent solid, very hard. Graphite has layered structure (weak forces between layers).
Correct Answer: (B)
Exercise 27
Why do ionic solids typically have higher melting points than molecular solids?
- (A) Ionic solids have weaker forces.
- (B) Ionic solids have strong electrostatic attractions.
- (C) Molecular solids have a continuous covalent network.
- (D) Molecular solids contain delocalized electrons.
해답 보기
Ionic solids are held by strong electrostatic forces between ions.
Correct Answer: (B)
Exercise 28
According to Coulomb’s Law, which factor does NOT directly affect ionic bond strength?
- (A) The charges on the ions
- (B) The distance between ions
- (C) The number of valence electrons (outer electrons) per se
- (D) The types of ions (which affects charge/radius)
View Answer
Coulomb’s Law depends on charge magnitude (q1q2) and distance (r), not directly the total # of valence electrons apart from how they form the ions.
Correct Answer: (C)
Exercise 29
Which compound contains both ionic and covalent bonds?
- (A) NaCl
- (B) CO2
- (C) NH4NO3
- (D) CH4
View Answer
Ammonium nitrate has ionic bonding between NH4+ and NO3–, plus covalent bonds within those ions.
Correct Answer: (C)
Exercise 30
Which best explains why water (H2O) has a higher boiling point than hydrogen sulfide (H2S)?
- (A) H2O has stronger hydrogen bonding.
- (B) H2S has more polar bonds.
- (C) H2O has weaker IMF.
- (D) H2S is a network covalent solid.
해답 보기
Water forms strong hydrogen bonds; H2S does not.
Correct Answer: (A)
Exercise 31
Which explains why magnesium (Mg) has a stronger metallic bond than lithium (Li)?
- (A) Mg has more delocalized electrons (2 vs 1).
- (B) Mg is larger, so stronger bond.
- (C) Mg has higher ionization energy.
- (D) Mg has lower electronegativity.
해답 보기
Magnesium can contribute two electrons to the “sea”, strengthening the metallic bond.
Correct Answer: (A)
Exercise 32
Based on Coulomb’s Law, which ionic compound has the greatest lattice energy?
- (A) CaO
- (B) AlN
- (C) SrS
- (D) KF
View Answer
AlN with Al3+ and N3- yields higher charge product and smaller ions → highest lattice energy.
Correct Answer: (B)
Exercise 33
Which molecular geometry corresponds to sp3 hybridization and one lone pair?
- (A) Trigonal Planar
- (B) Tetrahedral
- (C) Trigonal Pyramidal
- (D) Linear
해답 보기
sp3 with 1 lone pair → trigonal pyramidal (like NH3).
Correct Answer: (C)
Exercise 34
Why is silicon (Si) classified as a network covalent solid rather than a molecular solid?
- (A) Si forms discrete Si4 molecules.
- (B) Si forms a 3D network of covalent bonds.
- (C) Si has delocalized electrons like metals.
- (D) Si exists as isolated atoms.
해답 보기
Silicon has a continuous 3D covalent network (like diamond).
Correct Answer: (B)
Exercise 35
Which statement about bond energy & bond length is accurate?
- (A) Triple bonds are longer/weaker than single bonds.
- (B) Double bonds are longer than single but lower bond energy.
- (C) More shared pairs → shorter bond length & higher bond energy.
- (D) All have same bond energy.
해답 보기
Increasing shared pairs = shorter length & stronger bond.
Correct Answer: (C)
Exercise 36
Which statement distinguishes interstitial vs. substitutional alloys?
- (A) Interstitial: similar-size atoms replace each other; Substitutional: smaller fill holes.
- (B) Substitutional: different-size fill holes; Interstitial: similar-size replace.
- (C) Interstitial: different-size fill holes; Substitutional: comparable radii replace.
- (D) Both exclusively have similar radii atoms.
해답 보기
Interstitial = smaller atoms filling holes; Substitutional = similar-size atoms replacing some metal atoms.
Correct Answer: (C)
Exercise 37
Arrange in order of highest to lowest lattice energy: MgO, LiF, NaCl, KBr.
- (A) MgO > LiF > NaCl > KBr
- (B) LiF > MgO > NaCl > KBr
- (C) NaCl > MgO > LiF > KBr
- (D) KBr > NaCl > LiF > MgO
해답 보기
MgO has highest (2+/2-), then LiF (small ions), then NaCl, then KBr.
Correct Answer: (A)
Exercise 38
Which molecule exhibits resonance due to delocalized electrons?
- (A) CH4
- (B) C2H6
- (C) C6H6 (Benzene)
- (D) CCl4
해답 보기
Benzene has resonance among ring double bonds.
Correct Answer: (C)
Exercise 39
How does bond polarity relate to molecular polarity?
- (A) All molecules with polar bonds are polar.
- (B) A molecule can be nonpolar even if it has polar bonds.
- (C) Molecules with nonpolar bonds are always polar.
- (D) Molecular polarity is unrelated to bond polarity.
View Answer
Dipoles can cancel if geometry is symmetrical. So a molecule with polar bonds can be nonpolar overall.
Correct Answer: (B)
Exercise 40
Which molecule has a trigonal pyramidal geometry and is polar due to a lone pair on the central atom?
- (A) CCl4
- (B) NH3
- (C) BF3
- (D) H2O
View Answer
NH3 is trigonal pyramidal (3 bonds, 1 lone pair) and polar.
Correct Answer: (B)
Exercise 41
Which ion exhibits resonance due to delocalized electrons?
- (A) NH4+
- (B) SO42-
- (C) OH–
- (D) Na+
View Answer
Sulfate (SO4 2-) has resonance among the S=O bonds.
Correct Answer: (B)
Exercise 42
Which best explains HF’s higher boiling point vs. other hydrogen halides (HCl, HBr, HI)?
- (A) HF has stronger London dispersion forces.
- (B) HF forms ionic bonds due to less shielding.
- (C) HF forms strong hydrogen bonds via highly electronegative F.
- (D) HF is smaller, enabling closer packing.
View Answer
HF has strong hydrogen bonding, whereas HCl/HBr/HI rely on weaker dipole or dispersion.
Correct Answer: (C)
Exercise 43
Which molecule is nonpolar yet has polar bonds?
- (A) H2O
- (B) CO2
- (C) NH3
- (D) HF
View Answer
CO2 is linear with bond dipoles canceling out, making it nonpolar.
Correct Answer: (B)
Exercise 44
Which molecular geometry has the highest number of electron pairs around the central atom?
- (A) Linear
- (B) Trigonal Planar
- (C) Tetrahedral
- (D) Octahedral
View Answer
Octahedral has six electron pairs around the center.
Correct Answer: (D)
Exercise 45
Why does diamond have a higher melting point than O2?
- (A) Diamond has stronger hydrogen bonds.
- (B) Diamond is a 3D network solid; O2 is just molecular with weak intermolecular forces.
- (C) O2 has heavier molecular weight.
- (D) Diamond has delocalized electrons.
View Answer
Diamond is a network covalent solid, very strong bonds. O2 has weak IMF.
Correct Answer: (B)
Exercise 46
Why do molecular solids generally have lower melting points than ionic solids?
- (A) Molecular solids have stronger covalent bonds between molecules.
- (B) Molecular solids have weaker intermolecular forces vs. strong ionic bonds.
- (C) Ionic solids have larger ions.
- (D) Ionic solids do not conduct electricity.
View Answer
Molecular solids rely on weaker IMF, while ionic solids have strong electrostatic attractions.
Correct Answer: (B)
Exercise 47
Which statement about network covalent solids and their conductivity is correct?
- (A) Diamond conducts electricity as all electrons are free.
- (B) Silicon is a conductor at room temp. due to free electrons.
- (C) Graphite conducts (delocalized electrons), silicon & SiO2 do not.
- (D) SiO2 conducts electricity due to a regular lattice.
View Answer
Graphite is unique among network covalents in that it conducts electricity via delocalized electrons. Diamond, Si, SiO2 do not.
Correct Answer: (C)
Exercise 48
According to VSEPR, what is the geometry of SO2?
- (A) Linear
- (B) Trigonal Planar
- (C) Trigonal Pyramidal
- (D) Bent
해답 보기
SO2 has 2 bonding pairs + 1 lone pair → Bent geometry.
Correct Answer: (D)
Exercise 49
Which hybridization is associated with trigonal bipyramidal geometry?
- (A) sp
- (B) sp2
- (C) sp3
- (D) sp3d
View Answer
Trigonal bipyramidal → sp3d.
Correct Answer: (D)
Exercise 50
Which molecule has the lowest boiling point and why?
- (A) H2O
- (B) CH3OH (Methanol)
- (C) H2S
- (D) NH3
View Answer
H2S has weaker H-bonding or dipoles than H2O, CH3OH, NH3.
Correct Answer: (C)
Exercise 51
Which best describes the role of delocalized electrons in metallic bonding?
- (A) They form covalent bonds.
- (B) They localize between cations.
- (C) They move freely, allowing electrical conductivity.
- (D) They form ionic bonds.
View Answer
Delocalized electrons in metals roam freely, enabling conductivity.
Correct Answer: (C)
Exercise 52
Which molecule is expected to have the greatest bond polarity?
- (A) Cl2
- (B) H2O
- (C) CO2
- (D) HF
View Answer
HF has the largest electronegativity difference (H-F).
Correct Answer: (D)
Exercise 53
Which statement is true about network covalent solids vs. molecular solids?
- (A) Network covalents have lower melting points.
- (B) Network covalents are typically soft & brittle.
- (C) Network covalents do not conduct electricity (generally).
- (D) Network covalents have strong bonding throughout the structure.
View Answer
They have strong covalent bonds throughout, leading to high melting points, hardness, etc.
Correct Answer: (D)
Exercise 54
Which compound is expected to conduct electricity in the solid state?
- (A) Diamond (C)
- (B) Silicon dioxide (SiO2)
- (C) Graphite (C)
- (D) Sodium chloride (NaCl)
View Answer
Graphite can conduct as a solid. The others cannot (diamond, SiO2 do not conduct, NaCl is ionic—only in molten or aqueous form).
Correct Answer: (C)
Exercise 55
Which molecule is nonpolar despite having polar bonds?
- (A) HCl
- (B) CO2
- (C) NH3
- (D) HF
View Answer
CO2 is linear and dipoles cancel, so it is nonpolar.
Correct Answer: (B)
Exercise 56
Which best describes the hybridization of C in methane (CH4)?
- (A) sp
- (B) sp2
- (C) sp3
- (D) dsp3
View Answer
CH4 is tetrahedral → sp3.
Correct Answer: (C)
Exercise 57
Which compound primarily exhibits London dispersion forces in the liquid state?
- (A) H2O
- (B) CH4
- (C) NH3
- (D) HF
View Answer
CH4 is nonpolar, so only London dispersion forces.
Correct Answer: (B)
Exercise 58
Which molecule exhibits trigonal planar geometry?
- (A) CH4
- (B) NH3
- (C) BF3
- (D) H2O
View Answer
BF3 has 3 bonds, no lone pairs on B → trigonal planar.
Correct Answer: (C)
Exercise 59
Why do network covalent solids generally have higher melting points than molecular solids?
- (A) Network covalents have stronger IMFs.
- (B) They have extensive covalent bonds throughout the structure.
- (C) Molecular solids have bigger molecules with weaker bonds.
- (D) Molecular solids have delocalized electrons, making them easier to melt.
View Answer
Network covalent = strong covalent network, not just IMFs.
Correct Answer: (B)
Exercise 60
Which molecule has a square planar geometry?
- (A) XeF4
- (B) SF4
- (C) PF5
- (D) ClF3
View Answer
XeF4 is square planar (4 bonds, 2 lone pairs on Xe).
Correct Answer: (A)
Exercise 61
Which molecule would have the strongest dipole-dipole interactions in liquid state?
- (A) CCl4
- (B) NH3
- (C) SF6
- (D) CH4
View Answer
NH3 is polar with hydrogen bonding. Others are either nonpolar or less polar.
Correct Answer: (B)
Exercise 62
Why does NH3 have a higher boiling point than CH4?
- (A) NH3 has a larger mol. weight.
- (B) NH3 forms hydrogen bonds; CH4 has only dispersion.
- (C) CH4 is polar, NH3 is nonpolar.
- (D) NH3 has a symmetrical shape.
해답 보기
Ammonia forms H-bonds; methane does not → higher boiling point.
Correct Answer: (B)
Exercise 63
Which bonding type is responsible for the high melting point & hardness of diamond?
- (A) Metallic
- (B) Ionic
- (C) Covalent network
- (D) Van der Waals
View Answer
Diamond is a covalent network solid (sp3-bonded carbon network).
Correct Answer: (C)
Exercise 64
Which best explains why HF has a higher boiling point than HCl?
- (A) HF has stronger hydrogen bonding due to F’s electronegativity.
- (B) HCl has stronger dipoles.
- (C) HF has bigger molecules.
- (D) HCl forms a network covalent structure.
View Answer
Fluorine is highly electronegative → strong H-bonding in HF.
Correct Answer: (A)
Exercise 65
Which molecule is linear due to sp hybridization?
- (A) BeCl2
- (B) SO2
- (C) NH3
- (D) H2O
View Answer
BeCl2 is sp & linear (2 bonds, no lone pairs on Be).
Correct Answer: (A)
Exercise 66
Which molecule exhibits hydrogen bonding in the liquid state?
- (A) H2S
- (B) CH4
- (C) C2H5OH (Ethanol)
- (D) CCl4
해답 보기
Ethanol has an -OH group, enabling hydrogen bonding. Correct Answer: (C)
Exercise 67
Why does MgO have a higher lattice energy than NaCl?
- (A) MgO has bigger ions.
- (B) MgO has ions with higher charges.
- (C) NaCl has higher charge density.
- (D) NaCl forms stronger metallic bonds.
View Answer
Mg2+ and O2- → larger charge product than Na+, Cl–.
Correct Answer: (B)
Exercise 68
Which molecule has a see-saw geometry due to one lone pair on the central atom?
- (A) SF4
- (B) PCl5
- (C) ClF3
- (D) XeF2
View Answer
SF4 has 4 bonding pairs, 1 lone pair → see-saw. Correct Answer: (A)
Exercise 69
Which statement about geometry & hybridization is correct?
- (A) All linear molecules have sp3.
- (B) Tetrahedral molecules have sp3.
- (C) Trigonal pyramidal molecules have sp2.
- (D) Bent molecules have sp.
View Answer
Tetrahedral → sp3 (e.g. CH4).
Correct Answer: (B)
Exercise 70
Why does SiO2 have a high melting point?
- (A) Discrete molecules with strong H-bonds.
- (B) Continuous 3D network of strong covalent bonds.
- (C) Ionic bonds between Si4+ and O2-.
- (D) Metallic bonding with delocalized electrons.
View Answer
SiO2 is a network covalent solid (like quartz) with high melting point.
Correct Answer: (B)
Exercise 71
Why can metals like Cu conduct electricity, but nonmetals like S cannot?
- (A) Metals have free electrons, nonmetals do not.
- (B) Nonmetals have more protons blocking electrons.
- (C) Metals form ionic bonds, allowing electron flow.
- (D) Nonmetals have delocalized electrons that block conduction.
View Answer
Metals have a “sea of electrons” that move freely; nonmetals lack such delocalized electrons.
Correct Answer: (A)
Exercise 72
Why do ionic bonds typically result in high melting and boiling points?
- (A) Ionic bonds involve shared electrons (covalent).
- (B) Strong electrostatic attraction between ions requires lots of energy to break.
- (C) Delocalized electrons enhance ionic bonding.
- (D) Ionic bonds are weaker than metallic bonds.
View Answer
Ionic bonds are strong electrostatic forces; large energy is needed to break the lattice.
Correct Answer: (B)
Exercise 73
Which best describes the intermolecular forces in SiO2?
- (A) Hydrogen bonds
- (B) Dipole-dipole
- (C) London dispersion
- (D) Network covalent bonds
View Answer
SiO2 is a network solid with covalent bonds, not “intermolecular” forces in the typical sense.
Correct Answer: (D)
Exercise 74
Which molecule exhibits a net dipole moment?
- (A) CO2
- (B) BF3
- (C) NH3
- (D) C2H6
View Answer
NH3 has a trigonal pyramidal shape, net dipole. CO2, BF3 are symmetrical, C2H6 is also nonpolar.
Correct Answer: (C)
Exercise 75
Which statement about ionic solids is correct?
- (A) Good conductors in solid state.
- (B) Low melting points due to weak forces.
- (C) They are brittle and shatter under force.
- (D) They are malleable like metals.
View Answer
Ionic solids are brittle, not malleable, have high melting points, and do not conduct as solids.
Correct Answer: (C)
Exercise 76
Which molecule is nonpolar due to its symmetrical geometry despite polar bonds?
- (A) H2O
- (B) CCl4
- (C) NH3
- (D) HF
View Answer
CCl4 is tetrahedral, each C-Cl bond is polar but net dipole = 0 Correct Answer: (B)
Exercise 77
Why are hydrogen bonds stronger than London dispersion forces?
- (A) H-bonds involve full electron sharing (covalent).
- (B) H-bonds occur with highly electronegative atoms (N, O, F) creating strong dipoles.
- (C) London forces are a type of hydrogen bond.
- (D) H-bonds are weaker than dipole-dipole.
View Answer
Hydrogen bonding is a special, stronger form of dipole-dipole with high electronegativity differences.
Correct Answer: (B)
Exercise 78
Which molecule exhibits sp3 hybridization at the central atom?
- (A) CO2
- (B) NH3
- (C) BF3
- (D) XeF4
해답 보기
NH3 is sp3.
Correct Answer: (B)
Exercise 79
Which network covalent solid has a layered structure, making it soft & slippery?
- (A) Diamond
- (B) Silicon
- (C) Graphite
- (D) Silicon dioxide
View Answer
Graphite is layered carbon, easily sheared.
Correct Answer: (C)
Exercise 80
Which of the following best explains why network covalent solids like diamond and silicon dioxide do not conduct electricity?
Options:
- (A) They lack delocalized electrons.
- (B) They have high lattice energies.
- (C) They have symmetrical molecular geometries.
- (D) They possess lone pairs of electrons.
View Answer
Answer Explanation:
Network covalent solids like diamond and silicon dioxide have all their electrons involved in strong covalent bonds, leaving no delocalized electrons available to conduct electricity.
Correct Answer: (A) They lack delocalized electrons.
Exercise 81
Which of the following best describes the process of bond formation in covalent bonds?
Options:
- (A) Electrons are transferred from one atom to another.
- (B) Electrons are shared between two atoms.
- (C) Electrons become delocalized over a metal lattice.
- (D) Electrons are removed entirely from a molecule.
View Answer
Answer Explanation:
Covalent bonds form when two atoms share electrons to achieve stable electron configurations. This differs from ionic bonds (electron transfer) or metallic bonds (delocalized electrons).
Correct Answer: (B) Electrons are shared between two atoms.
Exercise 82
Which of the following statements correctly describes the relationship between bond energy and potential energy during bond formation?
Options:
- (A) Bond energy decreases as potential energy decreases.
- (B) Bond energy is inversely related to potential energy.
- (C) Bond energy is directly proportional to the difference in potential energy before and after bond formation.
- (D) Bond energy and potential energy are unrelated concepts.
View Answer
Answer Explanation:
The bond energy (or bond dissociation energy) corresponds to the difference in potential energy between separated atoms and bonded atoms. A larger difference means a higher bond energy.
Correct Answer: (C)
Exercise 83
Which of the following best explains why methane (CH4) has a tetrahedral geometry?
Options:
- (A) It has sp2 hybridization.
- (B) It has sp3 hybridization with no lone pairs.
- (C) It has sp hybridization with two lone pairs.
- (D) It has dsp3 hybridization.
View Answer
Answer Explanation:
In CH4, carbon forms four sp3-hybrid orbitals, each bonding to a hydrogen. No lone pairs remain on carbon, resulting in a tetrahedral shape (~109.5°).
Correct Answer: (B)
Exercise 84
Which of the following best describes the trend in bond strength among the hydrogen halides: HF, HCl, HBr, and HI?
Options:
- (A) HF > HCl > HBr > HI
- (B) HI > HBr > HCl > HF
- (C) HCl > HF > HI > HBr
- (D) HBr > HI > HF > HCl
View Answer
Answer Explanation:
As halide atoms increase in size (Cl → Br → I), bond length increases and bond strength decreases. HF is the shortest and strongest, then HCl, HBr, and finally HI as the weakest.
Correct Answer: (A)
Exercise 85
Which of the following best explains why hydrogen sulfide (H2S) has a lower boiling point than hydrogen peroxide (H2O2)?
Options:
- (A) H2S has stronger hydrogen bonds than H2O2.
- (B) H2O2 has stronger hydrogen bonds due to additional hydroxyl groups.
- (C) H2S is a larger molecule, resulting in weaker intermolecular forces.
- (D) H2O2 has a lower molecular weight, leading to a lower boiling point.
View Answer
Answer Explanation:
Hydrogen peroxide (H2O2) can form more extensive hydrogen bonding because it has two —OH groups, resulting in stronger intermolecular forces and a higher boiling point than H2S (which cannot form such strong hydrogen bonds).
Correct Answer: (B)
Exercise 86
Which of the following best explains the difference in electrical conductivity between metallic solids and molecular solids?
Options:
- (A) Metallic solids have delocalized electrons that can move freely, while molecular solids do not.
- (B) Molecular solids have delocalized electrons, while metallic solids do not.
- (C) Both metallic and molecular solids have delocalized electrons, but molecular solids have stronger bonds.
- (D) Neither metallic nor molecular solids have delocalized electrons.
View Answer
Answer Explanation:
Metals have a “sea of electrons” free to move throughout the lattice, enabling conductivity. Molecular solids, composed of discrete molecules with localized electrons, generally cannot conduct electricity in the solid state.
Correct Answer: (A)